3x^2-20x-132=0

Solution for 3x^2-20x-132=0 equation:

3x^2-20x-132=0

a = 3; b = -20; c = -132;
Δ = b2-4ac
Δ = -202-4·3·(-132)
Δ = 1984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1984}=\sqrt{64*31}=\sqrt{64}*\sqrt{31}=8\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-8\sqrt{31}}{2*3}=\frac{20-8\sqrt{31}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+8\sqrt{31}}{2*3}=\frac{20+8\sqrt{31}}{6}
$